Harga pH larutan basa kuat M OH2 0,005 M adalah

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T12/15/2016

Seperti yang https://www.avkimia.com/saya jelahttps://www.avkimia.com/skan https://www.avkimia.com/sebelumnya, zat yang berhttps://www.avkimia.com/sifat bahttps://www.avkimia.com/sa memiliki pH behttps://www.avkimia.com/sar dari 7 - 14. Dalam bahttps://www.avkimia.com/sa tentu tidak ada ion H+, yang ada adalah ion OH-, https://www.avkimia.com/sehingga yang kita hitung pertama kali untuk mencari pH bahttps://www.avkimia.com/sanya adalah konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si ion OH- nya. Mencari konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si ion OH- dari bahttps://www.avkimia.com/sa kuat dan lemah tentunya berbeda https://www.avkimia.com/sama halnya dengan ahttps://www.avkimia.com/sam dan bahttps://www.avkimia.com/sa kuat. Ahttps://www.avkimia.com/salkan kalian ingat rumuhttps://www.avkimia.com/s mencari konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si H+ dari ahttps://www.avkimia.com/sam kuat dan lemah, maka pahttps://www.avkimia.com/sti kalian akan mudah mengingat rumuhttps://www.avkimia.com/s OH- bahttps://www.avkimia.com/sa kuat dan lemah yang https://www.avkimia.com/sejatinya mirip. Yang perlu kalian ingat adalah : pH&nbhttps://www.avkimia.com/sp;+ pOH = pKw = 14 pH = 14 - pOH

A. pH Bahttps://www.avkimia.com/sa kuat

Bahttps://www.avkimia.com/sa kuat adalah bahttps://www.avkimia.com/sa yang mengion https://www.avkimia.com/sempurna https://www.avkimia.com/sehingga konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si OH-nya akan bergantung pada valenhttps://www.avkimia.com/si bahttps://www.avkimia.com/sa/jumlah ion OH- dan konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si bahttps://www.avkimia.com/sa kuatnya. LOH(aq) ==>L+(aq)&nbhttps://www.avkimia.com/sp;+ OH-(aq) 0,1M &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;0,1 M M(OH)2(aq) ==> M2+(aq)&nbhttps://www.avkimia.com/sp;+ 2OH-(aq) 0,1 M &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; = 2 x 0,1 M = 0,2 M Dari contoh diatahttps://www.avkimia.com/s dapat diambil kehttps://www.avkimia.com/simpulan bahwa untuk mencari [OH-] digunakan rumuhttps://www.avkimia.com/s https://www.avkimia.com/sebagai berikut : [OH-] = Valenhttps://www.avkimia.com/si bahttps://www.avkimia.com/sa x M

Contoh Soal

Soal 1 :Menghitung pH jika diketahui konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si bahttps://www.avkimia.com/sa kuatya Tentukanlah pH dari : a. Larutan KOH 0,02 M b. Larutan Ca(OH)2 0,005 &nbhttps://www.avkimia.com/sp;M

Pembahahttps://www.avkimia.com/san :

a. KOH 0,02 M &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; Reakhttps://www.avkimia.com/si ionihttps://www.avkimia.com/sahttps://www.avkimia.com/si KOH &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; KOH(aq) ==> K+(aq)&nbhttps://www.avkimia.com/sp;+ OH-(aq) &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; [OH-] = Valenhttps://www.avkimia.com/si Bahttps://www.avkimia.com/sa x M

&nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; https://www.avkimia.com/s&nbhttps://www.avkimia.com/sp;= 2 - log 2 &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;pH = 14 - pOH &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;= 14 - (2 - log 2) &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;= 12&nbhttps://www.avkimia.com/sp;+ log 2 b Larutan Ca(OH)2 0,005 M &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;Reakhttps://www.avkimia.com/si ionihttps://www.avkimia.com/sahttps://www.avkimia.com/si Ca(OH)2 &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;Ca(OH)2(aq) ==> Ca2+(aq)&nbhttps://www.avkimia.com/sp;+ 2OH-(aq) &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;[OH-] = Valenhttps://www.avkimia.com/si bahttps://www.avkimia.com/sa x M

Soal 2 : Menghitung pH bahttps://www.avkimia.com/sa ynag diketahui mahttps://www.avkimia.com/shttps://www.avkimia.com/sanya

Sebanyak 3,7 gram Ca(OH)2 dilarutkan dalam 5 L air. Berapa pH larutan itu? ( Ar Ca = 40, O = 16 dan H= 1)

Pembahahttps://www.avkimia.com/san :

Yang kita butuhkan kan dalam https://www.avkimia.com/satuan konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si, jadi langkah pertama kita adalah mengubah mahttps://www.avkimia.com/shttps://www.avkimia.com/sa menjadi konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si. Mol Ca(OH)2 = gr/Mr =3,7/74 = 0,05 mol

M Ca(OH)2 = n/V = 0,05/5 = 0,01 =

Nah https://www.avkimia.com/setelah dapat konhttps://www.avkimia.com/sentrahttps://www.avkimia.com/si Ca(OH)2, maka langkah akan https://www.avkimia.com/sangat mudah dalam menghitung pHnya. Reakhttps://www.avkimia.com/si ionihttps://www.avkimia.com/sahttps://www.avkimia.com/si Ca(OH)2 Ca(OH)2(aq) ==> Ca2+(aq)&nbhttps://www.avkimia.com/sp;+ 2OH-(aq) [OH-] = valenhttps://www.avkimia.com/si bahttps://www.avkimia.com/sa x M

&nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;= - log&nbhttps://www.avkimia.com/sp;

Soal 3 :Mencari mahttps://www.avkimia.com/shttps://www.avkimia.com/sa bahttps://www.avkimia.com/shttps://www.avkimia.com/sa yang akan dilarutkan jika diketahui pH bahttps://www.avkimia.com/sanya

Berapa gram NaOH diperlukan untuk membuat 10 L larutan dengan pH = 12?

Pembahahttps://www.avkimia.com/san :

Ini kebalikan dari https://www.avkimia.com/soal no 2, jadi kita mulai dari data pH nya. Karena NaOH adalah bahttps://www.avkimia.com/sa, maka yang diperlukan adalah pOH untuk mencari [OH-] nya. pH = 12 ==> pOH = 14 - pH = 14 - 12 = 2

[OH-] =&nbhttps://www.avkimia.com/sp;

[OH-] = Valenhttps://www.avkimia.com/si x M &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; M = [OH-]/Valenhttps://www.avkimia.com/si bahttps://www.avkimia.com/sa

&nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; =&nbhttps://www.avkimia.com/sp;/1

B. pH Bahttps://www.avkimia.com/sa Lemah

Bahttps://www.avkimia.com/sa lemah adalah bahttps://www.avkimia.com/sa yang tidak mengion https://www.avkimia.com/sempurna, https://www.avkimia.com/sehingga untuk mencari harga [OH-] digunakan rumuhttps://www.avkimia.com/s https://www.avkimia.com/sebagai berikut :

[OH-] =

Dengan Kb adalah konhttps://www.avkimia.com/stanta bahttps://www.avkimia.com/sa lemah dan M adalah molaritahttps://www.avkimia.com/snya. Rumuhttps://www.avkimia.com/s ini digunakan jika dalam https://www.avkimia.com/soal diketahui Kb nya.

Jika yang diketahui adalah derajat ionihttps://www.avkimia.com/sahttps://www.avkimia.com/sinya (

) maka rumuhttps://www.avkimia.com/s yang digunakan untuk mencari [OH-] adalah https://www.avkimia.com/sebagai berikut :

[OH-] =&nbhttps://www.avkimia.com/sp;&nbhttps://www.avkimia.com/sp;x M

Contoh Soal :

Tentukanlah pH larutan NH3 0,001 M jika diketahui Kb = ?

Pembahahttps://www.avkimia.com/san :

Reakhttps://www.avkimia.com/si ionihttps://www.avkimia.com/sahttps://www.avkimia.com/sinya : NH3(aq)&nbhttps://www.avkimia.com/sp;+ H2O(l) ,==> &nbhttps://www.avkimia.com/sp;NH4+(aq)&nbhttps://www.avkimia.com/sp;+ OH-(aq)

[OH-] =&nbhttps://www.avkimia.com/sp;

&nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp;= - log&nbhttps://www.avkimia.com/sp;

&nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; &nbhttps://www.avkimia.com/sp; = 11

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