Answer VerifiedHint: We know that the molarity is the most generally utilized unit of fixation and is indicated by M. It is characterized as no. of moles of solute present in 1 liter of solution. Consequently,Formula used to calculate molarity of the solution is,$Molarity = \dfrac{{{\text{Moles of solute}}}}{{{\text{Volume of solution(L)}}}}$ Complete answer: Note: We need to know that most of the responses occur in solutions thus it is critical to see how the measure of substance is communicated when it is available in the solution. There are numerous manners by which the measure of substances in solution is communicated:Molality:We need to remember that the molality (m) is characterized as the quantity of moles of solute per kilogram of dissolvable.$Molality = \dfrac{{{\text{Moles of solute}}}}{{{\text{Kilograms of dissolvable}}}}$On the off chance that ninety eight gram of sulphuric acid is available in one kg of water then it is one molal solution of Sulphuric acid in water. Furthermore, consequently molality will be one Normality:We have to know that the normality is characterized as the quantity of counterparts per liter of solution: $Normality = \dfrac{{{\text{Number of counterparts}}}}{{1{\text{ L of arrangement}}}}$ |