Write a program that rotates the elements of a list so that the element at the first index

[Type C]Q4. Write a program that rotates the elements of a list so that the element at the first index moves to the second index, the element in the second index moves to the third index, etc, and the element in the last index moves to the first index.

7. Write a program that rotates the elements of a list so that the element at the first index moves to the second index, the element in the second index moves to the third index, etc., and the element in the last index moves to the first index.

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HomeList Manipulation

Python program to right rotate a list by n

Given a list, right rotate the list by n position.

Examples :

Input : n = 2 List_1 = [1, 2, 3, 4, 5, 6] Output : List_1 = [5, 6, 1, 2, 3, 4] We get output list after right rotating (clockwise) given list by 2. Input : n = 3 List_1 = [3, 0, 1, 4, 2, 3] Output : List_1 = [4, 2, 3, 3, 0, 1]
Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach #1 : Traverse the first list one by one and then put the elements at required places in a second list.




# Python program to right rotate a list by n
# Returns the rotated list
def rightRotate(lists, num):
output_list = []
# Will add values from n to the new list
for item in range(len(lists) - num, len(lists)):
output_list.append(lists[item])
# Will add the values before
# n to the end of new list
for item in range(0, len(lists) - num):
output_list.append(lists[item])
return output_list
# Driver Code
rotate_num = 3
list_1 = [1, 2, 3, 4, 5, 6]
print(rightRotate(list_1, rotate_num))

Output :



[4, 5, 6, 1, 2, 3]

Time complexity : O(n)

Approach #2 : Another approach to solve this problem by using slicing technique. One way of slicing list is by using len() method.




# Python program to right rotate
# a list by n using list slicing
n = 3
list_1 = [1, 2, 3, 4, 5, 6]
list_1 = (list_1[len(list_1) - n:len(list_1)]
+ list_1[0:len(list_1) - n])
print(list_1)

Output:

[4, 5, 6, 1, 2, 3]

Approach #3 : In the above method, last n elements of list_1 was taken and then remaining elements of list_1. Another way is without using len() method.




# Right Rotating a list to n positions
n = 8
list_1 = [1, 2, 3, 4, 5, 6]
if n>len(list_1):
n = int(n%len(list_1))
list_1 = (list_1[-n:] + list_1[:-n])
print(list_1)

Output :

[4, 5, 6, 1, 2, 3]

Time complexity : O(n)

Note : list_1[:] will return the whole list as the blank space on left of slicing operator refers to start of list i.e 0 and blank space on right refers to ending position of list.

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