What is the molarity of a solution containing 10g of NaOH in 500mL of solution

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What is the molarity of a solution containing $$10g$$ of $$NaOH$$ in $$500\ mL$$ of the solution?

• A

  $$0.25\ mol$$ $${L}^{-1}$$

• B

  $$0.75\ mol$$ $${L}^{-1}$$

• C

  $$0.5\ mol$$ $${L}^{-1}$$

• D

  $$1.25\ mol$$ $${L}^{-1}$$

Molar mass of $$NaOH$$ = $$40g/mol$$

No of moles of $$NaOH$$ = $$\dfrac{10}{40}=0.25mol$$

therefore Molarity = $$\dfrac{0.25\times 1000}{500}=\dfrac{250}{500} = 0.5 molL^{-1}$$

Hence option $$C$$ is correct.

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