Definitions Solute-the substance being dissolved Solvent-the substance doing the dissolving (the larger amount) Solution- a homogeneous mixture of the solute and the solvent Solution= solvent + solute Aqueous (aq)= water solution Tincture= alcohol solution Amalgam= Mercury solution Molarity (M)- is the molar concentration of a solution measured in moles of solute per liter of solution. The molarity definition is based on the volume of the solution, NOT the volume of water. Vocab. Lesson Incorrect= The solution is 5.0 Molarity. Correct= The solution is 5.0 Molar. Example Problems Level 1- Given moles and liters Determine the molarity when 3.0 moles of sucrose are dissolved to make 2.0 liters of solution.
Level 2- Given Molarity and liters of solution Determine the number of moles of salt dissolved in 5.0 liters of a 0.50M solution of salt water.
cross multiply, X= 2.5 mols Level 3- Given grams (instead of moles) and liters of solution Determine the molarity when 117g of NaCl are dissolved to make 0.500 liters of solution. 1st convert to moles, 2nd plug into the molarity equation 117g NaCl( 1mol/58.5g)= 2.00mol NaCl
Level 4-Given grams (instead of moles) and milliliters of solution (instead of liters) Determine the molarity when 55.5g of CaCl2 are dissolved to make 250.mL of solution. 1st convert to moles, 2nd convert to liters, 3rd plug into the molarity equation 55.5g CaCl2( 1mol/111g)= 0.500mol CaCl2 250.ml( 1L/1000mL) =0.250L
Past Regents Questions-Follow link to check the answers Jan 2003-44 What is the molarity of a solution of NaOH if 2 liters of the solution contains 4 moles of NaOH?
Jan. 04-41 What is the molarity of a solution containing 20 grams of NaOH in 500 milliliters of solution? (1) 1 M (2) 2 M (3) 0.04 M (4) 0.5 M Jan 2002-42 What is the molarity of a solution that contains 0.50 mole of NaOH in 0.50 liter of solution?
Aug. 2006-42 How many total moles of KNO3 must be dissolved in water to make 1.5 liters of a 2.0 M solution? (1) 0.50 mol (2) 2.0 mol (3) 3.0 mol (4) 1.3 mol Aug 2005- 41 What is the total number of moles of NaCl(s) needed to make 3.0 liters of a 2.0 M NaCl solution?(1) 1.0 mol (3) 6.0 mol (2) 0.70 mol (4) 8.0 mol June 2006- 16 Molarity is defined as the(1) moles of solute per kilogram of solvent(2) moles of solute per liter of solution(3) mass of a solution (4) volume of a solvent Aug 2008- 15 Which phrase describes the molarity of a solution?(1) liters of solute per mole of solution(2) liters of solution per mole of solution(3) moles of solute per liter of solution (4) moles of solution per liter of solution June 2009-46 Which sample of HCl(aq) contains the greatest number of moles of solute particles? June 2007- 13 A 3.0 M HCl(aq) solution contains a total of(1) 3.0 grams of HCl per liter of water(2) 3.0 grams of HCl per mole of solution(3) 3.0 moles of HCl per liter of solution (4) 3.0 moles of HCl per mole of water June 2010-14 The molarity of an aqueous solution of NaCl is defined as the(1) grams of NaCl per liter of water(2) grams of NaCl per liter of solution(3) moles of NaCl per liter of water (4) moles of NaCl per liter of solution Jan 2008- 15 Which unit can be used to express solution concentration?(1) J/mol (3) mol/L (2) L/mol (4) mol/s Jan 04-41 What is the Molarity of a solution containing 20 grams of NaOH in 500 milliliters of solution?(1) 1 M (3) 0.04 M (2) 2 M (4) 0.5 M Jan 2010-40 What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass =26 grams/mole)?(1) 1.3 M (3) 3.0 M (2) 2.0 M (4) 0.75 M on to ppm or Molality back to Math of Chemistry Links
The percentage concentration of any solution is most commonly expressed as mass percent: Mass % of any component of the solution = Other methods are: Volume % of a component = i.e. Mass by Volume percentage = Here's a point to be kept in mind : The concentration of a solution is most of the time expressed as the number of moles of solute present in 1 Liter of the solution (also called molarity ) (There are also other ways to express concentration. Please follow this link. ) EXAMPLE: (b) What is the molarity of a solution prepared by dissolving 15.0 g of sodium hydroxide in enough water to make a total of 225 mL of solution? Solution Moles of NaOH = 15.0 g NaOH × #(1"mol NaOH")/(40.00"g NaOH")# = 0.375 mol NaOH Volume = 225 mL × #(1"L")/(1000"mL")# = 0.225 L soln Molarity = #(0.375"mol")/(0.225"L")# = 1.67 mol/L
Let's address the question for both percent concentration by mass and for percent concentration by volume. Percent concentration by mass is defined as the mass of solute divided by the total mass of the solution and multiplied by 100%. So, #c% = m_(solute)/(m_(solution)) * 100%#, where #m_(solution) = m_(solvent) + m_(solute)# There are two ways to change a solution's concentration by mass
Let's take an example to better illustrate this concept. Say we dissolve 10.0g of a substance in 100.0g of water. Our concentration by mass will be #c% = (10.0g)/(10.0g + 100.0g) * 100% = 9.09%# Now let's try doubling the mass of the solute; the new concentration will be #c% = (2 * 10.0g)/(2*10.0g + 100.0g) * 100% = 16.7%# However, if we keep the mass of the solute at 10.0g and doubled the mass of the solvent (in this case, water), the concentration will be #c% = (10.0g)/(10.0g + 2*100.0g) * 100% = 4.76%# The same is true for percent concentration by volume, which is defined as the volume of the solute divided by the total volume of the solution and multiplied by 100%. #c_(volume)% = V_(solute)/(V_(solute) + V_(solvent)) * 100%# It's easy to see that manipulating either the volume of the solute or the volume of the solvent (or both) would change the solution's percent concentration by volume.
There are two types of percent concentration: percent by mass and percent by volume. PERCENT BY MASS Percent by mass (m/m) is the mass of solute divided by the total mass of the solution, multiplied by 100 %. Percent by mass = #"mass of solute"/"total mass of solution"# × 100 % Example What is the percent by mass of a solution that contains 26.5 g of glucose in 500 g of solution? Solution Percent by mass = #"mass of glucose"/"total mass of solution" × 100 % = (26.5"g")/(500"g")# × 100 % = 5.30 % PERCENT BY VOLUME Percent by volume (v/v) is the volume of solute divided by the total volume of the solution, multiplied by 100 %. Percent by volume = #"volume of solute"/"total volume of solution"# × 100 % Example How would you prepare 250 mL of 70 % (v/v) of rubbing alcohol Solution 70 % = #"volume of rubbing alcohol"/"total volume of solution" × 100 %# × 100 % So Volume of rubbing alcohol = volume of solution × #"70 %"/"100 %"# = 250 mL × #70/100# = 175 mL You would add enough water to 175 mL of rubbing alcohol to make a total of 250 mL of solution.
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