How do you find all occurrences of an element in a list?

%timeit

# create 2M element list random.seed(365) l = [random.choice(['s1', 's2', 's3', 's4']) for _ in range(2000000)]

Find the indices of one value

  • Find indices of a single element in a 2M element list with 4 unique elements
# np.where: convert list to array %%timeit a = np.array(l) np.where(a == 's1') [out]: 409 ms ± 41.9 ms per loop (mean ± std. dev. of 7 runs, 1 loop each) # list-comprehension: on list l %timeit [i for i, x in enumerate(l) if x == "s1"] [out]: 201 ms ± 24 ms per loop (mean ± std. dev. of 7 runs, 1 loop each) # filter: on list l %timeit list(filter(lambda i: l[i]=="s1", range(len(l)))) [out]: 344 ms ± 36.6 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)

Find the indices of all the values

  • Find indices of all unique elements in a 2M element list with 4 unique elements
# use np.where and np.unique: convert list to array %%timeit a = np.array(l) {v: np.where(a == v)[0].tolist() for v in np.unique(a)} [out]: 682 ms ± 28 ms per loop (mean ± std. dev. of 7 runs, 1 loop each) # list comprehension inside dict comprehension: on list l %timeit {req_word: [idx for idx, word in enumerate(l) if word == req_word] for req_word in set(l)} [out]: 713 ms ± 16.7 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)

1. Using enumerate() function

To get the index of all occurrences of an element in a list, you can use the built-in function enumerate(). It was introduced to solve the loop counter problem and can be used as follows:

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if __name__ == '__main__':
ints = [1, 3, 7, 5, 4, 3]
item = 3
for index, elem in enumerate(ints):
if elem == item:
print(f"{item} is found at index {index}")
'''
Output:
3 is found at index 1
3 is found at index 5
'''

DownloadRun Code


To get the list of all indices at once, use list comprehension with enumerate function:

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if __name__ == '__main__':
ints = [1, 3, 7, 5, 4, 3]
item = 3
indexes = [i for i, j in enumerate(ints) if j == item]
print(f"Item {item} is found at index {indexes}")
# Output: Item 3 is found at index [1, 5]

DownloadRun Code

Python: Get index of item in List

To find index of element in list in python, we are going to use a function list.index(),

list.index()

Python’s list data type provides this method to find the first index of a given element in list or a sub list i.e.

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list.index(x[, start[, end]])

Arguments :

  • x : Item to be searched in the list
  • start : If provided, search will start from this index. Default is 0.
  • end : If provided, search will end at this index. Default is the end of list.

Returns: A zero based index of first occurrence of given element in the list or range. If there is no such element then it raises a ValueError.

Important Point : list.index() returns the index in a 0 based manner i.e. first element in the list has index 0 and second element in index is 1.

Let’s use this function to find the indexes of a given item in the list,

Suppose we have a list of strings,

# List of strings list_of_elems = ['Hello', 'Ok', 'is', 'Ok', 'test', 'this', 'is', 'a', 'test', 'Ok']

Now let’s find the index of the first occurrence of item ‘Ok‘ in the list,

elem = 'Ok' # Find index position of first occurrence of 'Ok' in the list index_pos = list_of_elems.index(elem) print(f'First Index of element "{elem}" in the list : ', index_pos)

Output

First Index of element "Ok" in the list : 1

As in the list.index() we did not provided start & end arguments, so it searched for the ‘Ok‘ in the complete list. But returned the index position as soon as it encountered the first occurrence of ‘Ok‘ in the list.

But if searched item doesn’t exists in the list, then index() will raise ValueError. Therefore we need to be ready for this kind of scenario. For example,

list_of_elems = ['Hello', 'Ok', 'is', 'Ok', 'test', 'this', 'is', 'a', 'test', 'Ok'] elem = 'Why' try: index_pos = list_of_elems.index(elem) print(f'First Index of element "{elem}" in the list : ', index_pos) except ValueError as e: print(f'Element "{elem}" not found in the list: ', e)

Output

Element "Why" not found in the list: 'Why' is not in list

As ‘Why‘ was not present in the list, so list.index() raised ValueError.

Python | Count occurrences of an element in a list

Given a list in Python and a number x, count number of occurrences of x in the given list.
Examples:

Input : lst = [15, 6, 7, 10, 12, 20, 10, 28, 10] x = 10 Output : 3 10 appears three times in given list. Input : lst = [8, 6, 8, 10, 8, 20, 10, 8, 8] x = 16 Output : 0

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Method 1 (Simple approach)
We keep a counter that keeps on increasing if the required element is found in the list.




# Python code to count the number of occurrences
def countX(lst, x):
count = 0
for ele in lst:
if (ele == x):
count = count + 1
return count
# Driver Code
lst = [8, 6, 8, 10, 8, 20, 10, 8, 8]
x = 8
print('{} has occurred {} times'.format(x, countX(lst, x)))
Output: 8 has occurred 5 times

Method 2 (Using count())
The idea is to use list method count() to count number of occurrences.




# Python code to count the number of occurrences
def countX(lst, x):
return lst.count(x)
# Driver Code
lst = [8, 6, 8, 10, 8, 20, 10, 8, 8]
x = 8
print('{} has occurred {} times'.format(x, countX(lst, x)))
Output: 8 has occurred 5 times

Method 2 (Using Counter())
Counter method returns a dictionary with occurrences of all elements as a key-value pair, where key is the element and value is the number of times that element has occurred.




from collections import Counter
# declaring the list
l = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5]
# driver program
x = 3
d = Counter(l)
print('{} has occurred {} times'.format(x, d[x]))
Output: 3 has occurred 2 times

How do you find all occurrences of an element in a list?




Article Tags :
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Practice Tags :
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Python – Get the indices of all occurrences of an element in a list

Given a list, the task is to write a Python Program to get the indices of all occurrences of an element in a list.

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“python find all occurrences of element in list” Code Answer


get all indices of a value in list python
python by Shaunak on Mar 11 2020 Comment
3
Source: stackoverflow.com
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Utilization of the list.index() Method:

The index() is an in-built method of Python. For the implementation of Python code, we have installed the Spyder software (version 5). Next, we create a new project by tapping the “new file” option from the menu bar. The new file we created is named “temp4.py”.

In this program, we use the index() method of the list with the items passed as arguments. The items are birds’ names. Here bird_to_find defines the bird whose index we want to find in the list:

How do you find all occurrences of an element in a list?

We take a List of birds. By using the index() method, we have to know the index of the bird “turkey” in the list. The index() method responds to an integer that indicates the index of the first match of bird in the List.

Now, we have to run that code by hitting the “F5” button from the keyboard. The index of a list begins with 0. This means that the first item in the list has an index of 0, not 1. Then, the second item has an index of 1. So, the bird “turkey” is present at 6th position, and its index is 5:

How do you find all occurrences of an element in a list?