How do you check if a number is not repeated in a list Python?

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Python check if there is a repeated value in a list example

Simple example code.

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“how to check which number is not repeated in a list python” Code Answer
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Python check if there is a repeated value in a list example
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Non-Repeating Element
How to find duplicates from a list in Python
Check if a list has duplicate Elements using Sets

Method 1

Using for-loop and if statement.

numbers = [1, 2, 3, 4, 2, 3, 5] rep = [] for n in numbers: if numbers.count(n) > 1: if n not in rep: print("Repeated number: ", n) rep.append(n)

Output:

Method 2

It will find only the first repeated value.

numbers = [1, 2, 3, 4, 2, 3, 5] endLoop = False for n1 in range(0, len(numbers)): for n2 in range(1, len(numbers)): if numbers[n1] == numbers[n2] and n1 != n2: print(numbers) print(numbers[n1]) endLoop = True if endLoop: break

Output:

[1, 2, 3, 4, 2, 3, 5]
2

Method 3

Using set, it also finds first repeated values.

number = [1, 2, 3, 4, 2, 3, 5] def find_repeat(numbers): seen = set() for num in numbers: if num in seen: return num seen.add(num) res = find_repeat(number) print(res)

Method 4

Using NumPy, you have to import the NumPy module. But this is a different solution, where only counting a repetition of every element of the list.

import numpy as np numbers = [1, 2, 3, 4, 2, 3, 5] counts = np.bincount(numbers) np.where([counts > 1])[1] print(counts)

Output: [0 1 2 2 1 1]

Do comment if you have any questions or suggestions on this Python list tutorial.

Note: IDE:PyCharm2021.3 (Community Edition)

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AllPython Examplesare inPython3, so Maybe its different from python 2 or upgraded versions.

Degree in Computer Science and Engineer: App Developer and has multiple Programming languages experience. Enthusiasm for technology & like learning technical.

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Non-Repeating Element

Find the first non-repeating element in a given array of integers.

Examples:

Input : -1 2 -1 3 2 Output : 3 Explanation : The first number that does not repeat is : 3 Input : 9 4 9 6 7 4 Output : 6

How to find duplicates from a list in Python

Check if a list has duplicate Elements using Sets

We know that sets in Python contain only unique elements. We can use this property of sets to check if a list has duplicate elements or not.

For this, we will create a set from the elements of the list. After that, we will check the size of the list and the set. If the size of both the objects are equal, it will confirm that the list has no duplicate elements. If the size of the set is greater than the list, it will mean that the list contains duplicate elements. We can understand this from the following example.

def check_duplicate(l): mySet = set(l) if len(mySet) == len(l): print("List has no duplicate elements.") else: print("The list contains duplicate elements") list1 = [1, 2, 3, 4, 5, 6, 7] print("List1 is:", list1) check_duplicate(list1) list2 = [1, 2, 1, 2, 4, 6, 7] print("List2 is:", list2) check_duplicate(list2)

Output:

List1 is: [1, 2, 3, 4, 5, 6, 7] List has no duplicate elements. List2 is: [1, 2, 1, 2, 4, 6, 7] The list contains duplicate elements

In the above approach, we need to create a set from all the elements of the list. After that, we also check the size of the set and the list. These operations are very costly.

Instead of using this approach, we can search only for the first duplicate element. To do this, we will start from the first element of the list and will keep adding them to the set. Before adding the elements to the set, we will check if the element is already present in the set or not. If yes, the list contains duplicate elements. If we are able to add each element of the list to the set, the list does not contain any duplicate element. This can be understood from the following example.

def check_duplicate(l): visited = set() has_duplicate = False for element in l: if element in visited: print("The list contains duplicate elements.") has_duplicate = True break else: visited.add(element) if not has_duplicate: print("List has no duplicate elements.") list1 = [1, 2, 3, 4, 5, 6, 7] print("List1 is:", list1) check_duplicate(list1) list2 = [1, 2, 1, 2, 4, 6, 7] print("List2 is:", list2) check_duplicate(list2)

Output:

List1 is: [1, 2, 3, 4, 5, 6, 7] List has no duplicate elements. List2 is: [1, 2, 1, 2, 4, 6, 7] The list contains duplicate elements.