What is the value for standard temperature of 273.15k in ∘f?

Chemistry lessons? ⚗️ Our standard temperature and pressure calculator is a simple tool that can make your life easier! Here you can easily compute both the volume and the number of moles of a gas in standard conditions.

Read on to discover the theoretical basis for our calculations - find out what are the standard conditions of temperature and pressure and how to deal with different kinds of chemistry queries based on that subject.

Standard temperature and pressure (STP), a.k.a. standard conditions, describe the environment of a chemical reaction.

Elements that define standard conditions:

1. The standard temperature is equal to: 273.15 K = 0°C = 32°F 🌡️

   Easy to remember - the standard temperature is the freezing point for water!

2. The standard pressure is equal to: 1 atm = 760 Torr = 760 mm Hg = 101.35 kPa

   Easy to remember - the standard pressure is equal to 1 atmosphere.

3. 1 mol of ideal gas in these conditions has a volume of 22.4 Liters.

What are the STP conditions used for?

STP conditions are used to compare different sets of data in chemistry. If we describe every reaction like the one that takes place in standard conditions , we can easily see all the differences between them.

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Our standard temperature and pressure calculator requires four easy steps:

1. Enter the volume of the gas.
2. Enter the temperature at which the process is taking place.
3. Enter the pressure of the gas.
4. Your results are here! You will receive both the volume and the number of moles of your substance at standard conditions.

Remember, our calculators work both ways! Whatever it is you're trying to calculate, we're here for you. 😎

Standard temperature and pressure (STP) calculations are not as hard as they seem - just follow our example below!

1. We measured our substance at 350 Kelvins and 850 Torr. Its volume was equal to 5 liters.

• Our volume [V] = 5 L;
• Our temperature [T] = 350 K; and
• Our pressure [P] = 850 Torr.

1. First, let's calculate the volume of our substance in STP temperature and pressure conditions.

VSTP = V * (273.15/T) * (P/760)

This STP formula uses Kelvins, Torrs and Liters. Let's add our data:

VSTP = 5 * (273.15/350) * (850/760)

VSTP = 4.364 L

1. Now, it's time to calculate the number of moles.

MolesSTP = VSTP/22.4

MolesSTP = 4.364/22.4

MolesSTP = 0.195

The standard conditions calculations are based on the ideal gas law formula.

PV = nRT

Other equations that might be useful in such situations are:

🎈 Do you already know the difference between an ideal and real gas?

Celsius to Kelvin ►

0 degrees Kelvin is equal to -273.15 degrees Celsius:

0 K = -273.15 °C

The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273.15:

T(°C) = T(K) - 273.15

Example

Convert 300 Kelvin to degrees Celsius:

T(°C) = 300K - 273.15 = 26.85 °C

Kelvin to Celsius conversion table

Celsius to Kelvin ►

See also

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Temperature scales conversion calculator for converting between Fahrenheit °F, Celsius °C (Centigrade), Kelvin K, Reaumur °r and Rankine °R plus manual conversion formulas.

Enter Temperature Value:

Precision:

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To unit

Choose a temperature scale From unit:

Choose a temperature scale To unit:

This converter allows you to do instant conversions between various temperature measurements in °F, °C, K, °r, °R scales.
You may enter whole numbers, decimals or fractions ie: 7, 29.35, 15 3/4 and plus + or minus - signs as well.

Temperature Conversion Factors

Subtract 32 from the Fahrenheit figure, multiply by 5, then divide by 9 to get Centigrade figure.

from Celsius °C to Fahrenheit °F calculation:

Multiply Centigrade figure by 9, divide by 5, then add 32 to get Fahrenheit figure.

Kelvin calculation

To calculate Kelvin figure, simply add 273.15 number to the Celsius temperature degree and you get the temperature reading in Kelvin thermodynamic temperature unit:

K = °C + 273.15 and correspondingly.

Take the figure and you can manually convert it to Fahrenheit with:

K = °F + 459.67 × 5/9

Where the 5/9 is number 0.556 and, precisely even more accurate 0.55555555555555555555555555555556 (32 decimal points) to end up with the exact 273.15 mark correct metrics.

The formulae for temperature with minus degrees readings:

K = 273.15 − °C (below zero C value used)
K = 459.67 − °F × 5/9 (minus F value used)

Kelvin is not associated with thermal ° degree symbol just with capital letter K. Zero kelvins, 0 K, equals to coldest possible temperature that can be measured "absolute zero" which is the thermodynamic (absolute) temperature -459.67°F or -273.15°C on scales.

Chart: K > °C > °F

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