Print the integer list of integers separated by space in C

C program to input an array from a sequence of space-separated integers

Given a string S consisting of space-separated integers, the task is to write a C program to take the integers as input from the string S and store them in an array arr[].

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C program to input an array from a sequence of space-separated integers
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A single line contains integers separated by space

Examples:

Input: S = “1 2 3 4”
Output: {1, 2, 3, 4}

Input: S = “32 12”
Output: {32, 12}

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The idea is to solve the given problem is to use getchar() function to check if a ‘\n’ (newline) occurs is found while taking input and then stop the input. Follow the step below to solve the given problem:

Initialize a variable, say count, which is used to store the index of the array element.
Initialize an array arr[] of size 106 to store the elements into the array.
Iterate using a do-while loop until newLine occurs and perform the following steps:
- Store the current value at index count as scanf(“%d “, &arr[count]); and increment the value of count.
- If the next character is not endline, then continue. Otherwise, break out of the loop.
After completing the above steps, print the elements stored in the array.

Below is the implementation of the above approach:

// C program for the above approach
#include <stdio.h>

// Driver Code

int main()
{

// Stores the index where the

// element is to be inserted

int count = 0;

// Initialize an array

int a[1000000];

// Perform a do-while loop

do {

// Take input at position count

// and increment count

scanf("%d", &a[count++]);

// If '\n' (newline) has occurred

// or the whole array is filled,

// then exit the loop

// Otherwise, continue

} while (getchar() != '\n' && count < 100);

// Resize the array size to count

a[count];

// Print the array elements

for (int i = 0; i < count; i++) {

printf("%d, ", a[i]);

}

return 0;
}