How do you check if a word is in a list of strings Python?

Python | Test if string contains element from list

During web development in Python, we generally come across a problem where we need to test if a particular element from a given list lies as sub-string or not. This kind of problem is also very common in Machine Learning domain. Let’s discuss certain ways in which this can be done.
Method #1 : Using list comprehension
This problem can be solved using the list comprehension, in this, we check for the list and also with string elements if we can find a match, and return true, if we find one and false is not using the conditional statements.

Table of Contents Show

Python | Test if string contains element from list
Find a String in a List in Python
Using the ‘in’ operator
Using List Comprehension
Using the ‘any()’ method
Using filter and lambdas
Python Check if List Contains a String
“python check list of words in string” Code Answer
Python answers related to “python check list of words in string”
Python queries related to “python check list of words in string”
Check if element exists in list using python “in” Operator
Check if String Contains Substring in Python
using find() method
Using inoperator
using count() method
using str.index() method
using operator.contains() method

Python3

# Python3 code to demonstrate
# checking if string contains list element
# using list comprehension
# initializing string 

test_string = "There are 2 apples for 4 persons"
# initializing test list

test_list = ['apples', 'oranges']
# printing original string 

print("The original string : " + test_string)
# printing original list 

print("The original list : " + str(test_list))
# using list comprehension
# checking if string contains list element

res = [ele for ele in test_list if(ele in test_string)]
# print result

print("Does string contain any list element : " + str(bool(res)))

Output : The original string : There are 2 apples for 4 persons The original list : ['apples', 'oranges'] Does string contain any list element : True

Method #2 : Using any()
Using any function is the most classical way in which you can perform this task and also efficiently. This function checks for match in string with match of each element of list.

Python3

# Python3 code to demonstrate
# checking if string contains list element
# using list comprehension
# initializing string 

test_string = "There are 2 apples for 4 persons"
# initializing test list

test_list = ['apples', 'oranges']
# printing original string 

print("The original string : " + test_string)
# printing original list 

print("The original list : " + str(test_list))
# using list comprehension
# checking if string contains list element




res = any(ele in test_string for ele in test_list)
# print result

print("Does string contain any list element : " + str(res))

Output : The original string : There are 2 apples for 4 persons The original list : ['apples', 'oranges'] Does string contain any list element : True

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Find a String in a List in Python

There are various approaches to this problem, from the ease of use to efficiency.

Using the ‘in’ operator

We can use Python’s in operator to find a string in a list in Python. This takes in two operands a and b, and is of the form:

ret_value = a in b

Here, ret_value is a boolean, which evaluates to True if a lies inside b, and False otherwise.

We can directly use this operator in the following way:

a = [1, 2, 3] b = 4 if b in a: print('4 is present!') else: print('4 is not present')

Output

4 is not present

We can also convert this into a function, for ease of use.

def check_if_exists(x, ls): if x in ls: print(str(x) + ' is inside the list') else: print(str(x) + ' is not present in the list') ls = [1, 2, 3, 4, 'Hello', 'from', 'AskPython'] check_if_exists(2, ls) check_if_exists('Hello', ls) check_if_exists('Hi', ls)

Output

2 is inside the list Hello is inside the list Hi is not present in the list

This is the most commonly used, and recommended way to search for a string in a list. But, for illustration, we’ll show you other methods as well.

Using List Comprehension

Let’s take another case, where you wish to only check if the string is a part of another word on the list and return all such words where your word is a sub-string of the list item.

Consider the list below:

ls = ['Hello from AskPython', 'Hello', 'Hello boy!', 'Hi']

If you want to search for the substring Hello in all elements of the list, we can use list comprehensions in the following format:

ls = ['Hello from AskPython', 'Hello', 'Hello boy!', 'Hi'] matches = [match for match in ls if "Hello" in match] print(matches)

This is equivalent to the below code, which simply has two loops and checks for the condition.

ls = ['Hello from AskPython', 'Hello', 'Hello boy!', 'Hi'] matches = [] for match in ls: if "Hello" in match: matches.append(match) print(matches)

In both cases, the output will be:

['Hello from AskPython', 'Hello', 'Hello boy!']

As you can observe, in the output, all the matches contain the string Hello as a part of the string. Simple, isn’t it?

Using the ‘any()’ method

In case you want to check for the existence of the input string in any item of the list, We can use the any() method to check if this holds.

For example, if you wish to test whether ‘AskPython’ is a part of any of the items of the list, we can do the following:

ls = ['Hello from AskPython', 'Hello', 'Hello boy!', 'Hi'] if any("AskPython" in word for word in ls): print('\'AskPython\' is there inside the list!') else: print('\'AskPython\' is not there inside the list')

Output

'AskPython' is there inside the list!

Using filter and lambdas

We can also use the filter() method on a lambda function, which is a simple function that is only defined on that particular line. Think of lambda as a mini function, that cannot be reused after the call.

ls = ['Hello from AskPython', 'Hello', 'Hello boy!', 'Hi'] # The second parameter is the input iterable # The filter() applies the lambda to the iterable # and only returns all matches where the lambda evaluates # to true filter_object = filter(lambda a: 'AskPython' in a, ls) # Convert the filter object to list print(list(filter_object))

Output

['Hello from AskPython']

We do have what we expected! Only one string matched with our filter function, and that’s indeed what we get!

Python Check if List Contains a String

Python Python String Python List

Created: June-02, 2021 | Updated: July-18, 2021

Strings are a sequence of characters. Just like strings store characters at specific positions, we can use lists to store a collection of strings.

In this tutorial, we will get a string with specific values in a Python list.

“python check list of words in string” Code Answer

check if word contains a word in a list python

python by Worried Wildebeest on Jul 11 2020 Comment

Source: stackoverflow.com

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Check if element exists in list using python “in” Operator

Condition to check if element is in List :

elem in LIST
It will return True, if element exists in list else return false.

For example check if ‘at’ exists in list i.e.

''' check if element exist in list using 'in' ''' if 'at' in listOfStrings : print("Yes, 'at' found in List : " , listOfStrings)
Condition to check if element is not in List :
''' check if element NOT exist in list using 'in' ''' if 'time' not in listOfStrings : print("Yes, 'time' NOT found in List : " , listOfStrings)

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Check if String Contains Substring in Python

Let’s look at all the different ways in Python to check if a string contains a substring.

using find() method

find() method is to verify if a string contains a substring or not. If the string contains a substring, it returns the starting index of the substring; else returns -1 if it cannot find a substring.

Syntax: string.find(substring, start, end)

Parameters:

substring:substring that needs to be searched in a given string
start (Optional):Starting position where the substring needs to be searched within the string.
end(Optional):Ending position where suffix needs to be searched within the string.

Note:If start and end indexes are not provided, then by default, it takes 0 as start index and length-1 as end index.

word = 'Hello its a beautiful day' # returns first occurrence of Substring result = word.find('beautiful ') print ("Substring 'beautiful ' found at index:", result ) # Substring is searched with start index 2 print(word.find('its', 2)) # Substring is searched with start index 10 print(word.find('its', 10)) # Substring is searched between start index 4 and end index 10 print(word.find('its', 4, 10)) # Substring is searched start index 10 and end index 20 print(word.find('its ', 10, 20)) # How to use find() if (word.find('sunny') != -1): print ("Contains given substring ") else: print ("Doesn't contains given substring")

Output

Substring 'beautiful ' found at index: 12 6 -1 6 -1 Doesn't contains given substring

Using inoperator

The “in” operator checks if a substring is present within a string, returnsTRUEif found else returnsFALSE.

word = "Hello its a beautiful day" sub1="beautiful" sub2="sunny" print(sub1 in word) print(sub2 in word) #Output True False

using count() method

The count() method checks for the occurrence of a substring in a string; if not found, return 0.

word = "Hello its a beautiful day" sub1="beautiful" sub2="Hello" sub3="Sunny" print(word.count(sub1)) print(word.count(sub2)) print(word.count(sub3)) # Output 1 1 0

using str.index() method

The method checks that the given substring is present in a string. If the substring is not present in the string, it doesn’t return any value rather generates aValueError.

Syntax: string.index(substring)

word = "Hello its a beautiful day" try : result = word.index("beautiful") print ("beautiful is present in the string.") except : print ("beautiful is not present in the string.") # Output beautiful is present in the string.

using operator.contains() method

Using the operator module, we can search if the substring is present in a string.

Syntax: operator.contains(string,substring)

import operator word = "Hello its a beautiful day" if operator.contains(word, "beautiful"): print ("beautiful is present in the string.") else : print ("beautiful is not present in the string.") # Output beautiful is present in the string.