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(c) No.of moles of solute / Volume of solution in L,= 5.85/58.5 = 0.1/0.5 = 0.2 mol L,-1
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Calcium carbonate
NCERT - Chemistry Part-I
What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL? (i) 4 mol L-1 (ii) 20 molL-1 (iii) 0.2 molL-1 (iv) 2molL-1
Correct Answer: (iii) 0.2 molL-1
Explanation: The Molarity is defined as the number of moles per volume of the solution in litres.
Given,
Mass = 5.85g
Molar mass = 58.5 g/mol
Volume of the solution = 0.5 L
So,
Number of moles = mass/molar mass
Number of moles =5.85/58.5
Number of moles =0.1 mol
Hence,
Molarity = 0.1/0.5
Molarity = 0.2mol/L
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What will be the molarity of a solution, which contains 5.85 g of NaCl s per 500 mL ?a 4 mol L 1b 20 mol L 1c 0.2 mol L 1d 2 mol L 1
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