Program to find frequency of all elements in a list in Python

List frequency of elements in Python

PythonServer Side ProgrammingProgramming

In this article, we are going to learn how to find the frequency of elements in a list. We can solve the problem in different ways. Let's see two of them.

Follow the below steps to write the code.

  • Initialize the list with elements and an empty dictionary.
  • Iterate over the list of elements.
    • Check whether the element is present in the dictionary or not.
    • If the element is already present in the dictionary, then increase its count.
    • If the element is not present in the dictionary, then initialize its count with 1.
  • Print the dictionary.

2. Python program to find the frequency of each element in the array

In this program, we have an array of elements to count the occurrence of its each element. One of the approaches to resolve this problem is to maintain one array to store the counts of each element of the array. Loop through the array and count the occurrence of each element as frequency and store it in another array fr.

In the given array, 1 has appeared two times, so its frequency is 2, and 2 has appeared four times so have frequency 4 and so on.

ALGORITHM:

  • STEP 1: Declare and initialize an array arr.
  • STEP 2: Declare another array fr with the same size of array arr. It is used to store the frequencies of elements present in the array.
  • STEP 3: Variable visited will be initialized with the value -1. It is required to mark an element visited that is, it helps us to avoid counting the same element again.
  • STEP 4: The frequency of an element can be counted using two loops. One loop will be used to select an element from an array, and another loop will be used to compare the selected element with the rest of the array.
  • STEP 5: Initialize count to 1 in the first loop to maintain a count of each element. Increment its value by 1 if a duplicate element is found in the second loop since we have counted this element and didn't want to count it again. Mark this element as visited by setting fr[j] = visited. Store count of each element to fr.
  • STEP 6: Finally, print out the element along with its frequency.

PROGRAM:

Output:

---------------------------------------- Element | Frequency ---------------------------------------- 1 | 2 2 | 4 8 | 1 3 | 1 5 | 1 ----------------------------------------

Counting the frequencies in a list using dictionary in Python

Given an unsorted list of some elements(may or may not be integers), Find the frequency of each distinct element in the list using a dictionary.
Example:

Input : [1, 1, 1, 5, 5, 3, 1, 3, 3, 1, 4, 4, 4, 2, 2, 2, 2] Output : 1 : 5 2 : 4 3 : 3 4 : 3 5 : 2 Explanation : Here 1 occurs 5 times, 2 occurs 4 times and so on...

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

The problem can be solved in many ways. A simple approach would be to iterate over the list and use each distinct element of the list as a key of the dictionary and store the corresponding count of that key as values. Below is the Python code for this approach:

Python




# Python program to count the frequency of
# elements in a list using a dictionary
def CountFrequency(my_list):
# Creating an empty dictionary
freq = {}
for item in my_list:
if (item in freq):
freq[item] += 1
else:
freq[item] = 1
for key, value in freq.items():
print ("% d : % d"%(key, value))
# Driver function
if __name__ == "__main__":
my_list =[1, 1, 1, 5, 5, 3, 1, 3, 3, 1, 4, 4, 4, 2, 2, 2, 2]
CountFrequency(my_list)
Output: 1 : 5 2 : 4 3 : 3 4 : 3 5 : 2

Time Complexity:O(N), where N is the length of the list.



Alternative way: An alternative approach can be to use the list.count() method.

Python




# Python program to count the frequency of
# elements in a list using a dictionary
def CountFrequency(my_list):
# Creating an empty dictionary
freq = {}
for items in my_list:
freq[items] = my_list.count(items)
for key, value in freq.items():
print ("% d : % d"%(key, value))
# Driver function
if __name__ == "__main__":
my_list =[1, 1, 1, 5, 5, 3, 1, 3, 3, 1, 4, 4, 4, 2, 2, 2, 2]
CountFrequency(my_list)
Output: 1 : 5 2 : 4 3 : 3 4 : 3 5 : 2

Time Complexity:O(N2), where N is the length of the list. The time complexity list.count() is O(N) alone, and when used inside loop it will become O(N2).

Alternative way:An alternative approach can be to use the dict.get() method. This makes the program much more shorter and makes understand how get method is useful instead of if…else.

Python




# Python program to count the frequency of
# elements in a list using a dictionary
def CountFrequency(my_list):
# Creating an empty dictionary
count = {}
for i in [1, 1, 1, 5, 5, 3, 1, 3, 3, 1 ,4, 4, 4, 2, 2, 2, 2]:
count[i] = count.get(i, 0) + 1
return count
# Driver function
if __name__ == "__main__":
my_list =[1, 1, 1, 5, 5, 3, 1, 3, 3, 1, 4, 4, 4, 2, 2, 2, 2]
print(CountFrequency(my_list))
Output: {1: 5, 5: 2, 3: 3, 4: 3, 2: 4}

Related Article :
Count frequencies of all elements in array in Python using collections module




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Python | List frequency of elements

Sometimes we have the utility in which we require to find the frequency of elements in the list and the solution to this problem has been discussed many times. But sometimes we come across the task in which we require to find the number of lists that particular elements occur. Let’s discuss certain shorthands in which this can be done.

Method #1 : Using Counter() + set() + list comprehension
The combination of the above functions can be used to perform the task. The Counter function does the grouping, set function extracts the distinct elements as keys of dict and list comprehension check for its list occurrences.

Python3




# Python3 code to demonstrate
# list frequency of elements
# using Counter() + set() + list comprehension
from collections import Counter
# initializing list
test_list = [[3, 5, 4],
[6, 2, 4],
[1, 3, 6]]
# printing original list
print("The original list : " + str(test_list))
# using Counter() + set() + list comprehension
# list frequency of elements
res = dict(Counter(i for sub in test_list for i in set(sub)))
# printing result
print("The list frequency of elements is : " + str(res))
Output : The original list : [[3, 5, 4], [6, 2, 4], [1, 3, 6]] The list frequency of elements is : {1: 1, 2: 1, 3: 2, 4: 2, 5: 1, 6: 2}


Method #2 : Using Counter() + itertools.chain.from_iterable() + map() + set()
The above 4 functionalities can also be combined to achieve this particular task. The set function extracts the dictionary keys formed by the Counter, map function performs the task for all sublists and from_iterable function performs using iterators which is faster than list comprehension.

Python3




# Python3 code to demonstrate
# list frequency of elements
# using Counter() + itertools.chain.from_iterable() + map() + set()
from collections import Counter
from itertools import chain
# initializing list
test_list = [[3, 5, 4],
[6, 2, 4],
[1, 3, 6]]
# printing original list
print("The original list : " + str(test_list))
# using Counter() + itertools.chain.from_iterable() + map() + set()
# list frequency of elements
res = dict(Counter(chain.from_iterable(map(set, test_list))))
# printing result
print("The list frequency of elements is : " + str(res))
Output :

The original list : [[3, 5, 4], [6, 2, 4], [1, 3, 6]] The list frequency of elements is : {1: 1, 2: 1, 3: 2, 4: 2, 5: 1, 6: 2}

Method #3: Using python dictionary + get() method

Python dictionary provides a get method which returns the value corresponding to the key and if the key does not exist in the dictionary then it provides functionality to create the key and assign it a default value. We will use this functionality of a dictionary.

Python3




d = {}
test_list = [[3, 5, 4],
[6, 2, 4],
[1, 3, 6]]
for x in test_list:
for i in x:
d[i] = d.get(i,0) + 1
# Original list
print(f"The original list : {test_list}" )
# printing result
print(f"The list frequency of elements is : {d}" )

Output:

The original list : [[3, 5, 4], [6, 2, 4], [1, 3, 6]] The list frequency of elements is : {3: 2, 5: 1, 4: 2, 6: 2, 2: 1, 1: 1}

Method #4: Using Pandas

In this method we will use a python module named pandas(You can know more about pandas in this article) to find the frequency of the given data, here below is the code for it.

Python3




import pandas as pd
test_list = [3,5,4,3,3,4,5,2]
df1 = pd.Series(test_list).value_counts().sort_index().reset_index().reset_index(drop=True)
df1.columns = ['Element', 'Frequency']
# Original list
print(f"The original list : {test_list}" )
# printing result
print(f"The list frequency of elements is :\n {df1.to_string(index=False)}" )

Output:

The original list : [3, 5, 4, 3, 3, 4, 5, 2] The list frequency of elements is : Element Frequency 2 1 3 3 4 2 5 2




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“how to check frequency of elements in list in python” Code Answer’s


how to get frequency of each elements in a python list
python by Frantic Ferret on May 24 2021 Comment
9
Source: buggyprogrammer.com
list count frequency python
python by Cheerful Cormorant on Jul 15 2020 Comment
1
Source: stackoverflow.com
freq count in python
python by Amused Albatross on Jul 21 2020 Comment
3
find frequency of numbers in list python
python by icy_milktea27
on Dec 29 2020 Comment
2
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Python: Get the frequency of the elements in a list

Last update on April 13 2021 05:36:53 (UTC/GMT +8 hours)

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