Below are the three solutions:
Fastest is using a for loop and storing it in a Dict.
import time from collections import Counter def countElement(a): g = {} for i in a: if i in g: g[i] +=1 else: g[i] =1 return g z = [1,1,1,1,2,2,2,2,3,3,4,5,5,234,23,3,12,3,123,12,31,23,13,2,4,23,42,42,34,234,23,42,34,23,423,42,34,23,423,4,234,23,42,34,23,4,23,423,4,23,4] #Solution 1 - Faster st = time.monotonic() for i in range(1000000): b = countElement(z) et = time.monotonic() print(b) print('Simple for loop and storing it in dict - Duration: {}'.format(et - st)) #Solution 2 - Fast st = time.monotonic() for i in range(1000000): a = Counter(z) et = time.monotonic() print (a) print('Using collections.Counter - Duration: {}'.format(et - st)) #Solution 3 - Slow st = time.monotonic() for i in range(1000000): g = dict([(i, z.count(i)) for i in set(z)]) et = time.monotonic() print(g) print('Using list comprehension - Duration: {}'.format(et - st))Result
#Solution 1 - Faster{1: 4, 2: 5, 3: 4, 4: 6, 5: 2, 234: 3, 23: 10, 12: 2, 123: 1, 31: 1, 13: 1, 42: 5, 34: 4, 423: 3} Simple for loop and storing it in dict - Duration: 12.032000000000153
#Solution 2 - FastCounter({23: 10, 4: 6, 2: 5, 42: 5, 1: 4, 3: 4, 34: 4, 234: 3, 423: 3, 5: 2, 12: 2, 123: 1, 31: 1, 13: 1}) Using collections.Counter - Duration: 15.889999999999418
#Solution 3 - Slow{1: 4, 2: 5, 3: 4, 4: 6, 5: 2, 34: 4, 423: 3, 234: 3, 42: 5, 12: 2, 13: 1, 23: 10, 123: 1, 31: 1} Using list comprehension - Duration: 33.0
Python | Count occurrences of an element in a list
Given a list in Python and a number x, count number of occurrences of x in the given list.
Examples:
Recommended: Please try your approach on {IDE} first, before moving on to the solution.
Method 1 (Simple approach)
We keep a counter that keeps on increasing if the required element is found in the list.
Python3
|
# Python code to count the number of occurrences
def countX(lst, x):
count = 0
for ele in lst:
if (ele == x):
count = count + 1
return count
# Driver Code
lst = [8, 6, 8, 10, 8, 20, 10, 8, 8]
x = 8
print('{} has occurred {} times'.format(x, countX(lst, x)))
|
Method 2 (Using count())
The idea is to use list method count() to count number of occurrences.
Python3
|
# Python code to count the number of occurrences
def countX(lst, x):
return lst.count(x)
# Driver Code
lst = [8, 6, 8, 10, 8, 20, 10, 8, 8]
x = 8
print('{} has occurred {} times'.format(x, countX(lst, x)))
|
Method 2 (Using Counter())
Counter method returns a dictionary with occurrences of all elements as a key-value pair, where key is the element and value is the number of times that element has occurred.
Python3
|
from collections import Counter
# declaring the list
l = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5]
# driver program
x = 3
d = Counter(l)
print('{} has occurred {} times'.format(x, d[x]))
|
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Python List count()
In this tutorial, we will learn about the Python List count() method with the help of examples.
The count() method returns the number of times the specified element appears in the list.
Example
# create a list numbers = [2, 3, 5, 2, 11, 2, 7]# check the count of 2
count = numbers.count(2)
print('Count of 2:', count)
# Output: Count of 2: 3Python count() Function
The Python count() function works out how many times a value appears in a list or a string. It returns the number of times the value appears as an integer.
Here is the syntax for the count() function:
names = ["Lewis", "Jade", "Lewis"]
print(names.count("Lewis"))
Our code counts how many times “Lewis” appears in our list.
You can see that the count() method is added after a list value in this example. count() does not accept a list as an argument. The count() method expects that you pass the value for which you want to search in a list or a string as an argument.
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Start your career switch todaymethods to count occurences
- Method 1: Counting Occurrences using builtin count() function.
- Method 2: Using loops to count unique values and elements in the list.
- Method 3: Using Counter class.
Using built-in count() function to count occurrences in a list
The python has a built-in count() function which takes a value as an argument whose count you want to find in the list. It will return an integer value that represents the number of times a specified item occurs in the list. If the integer does not exist, it returns 0.
following is the code To count occurences of an element in a list in python
# Create a list of integers list1 = [1, 2, 2, 7, 2, 9, 1, 4, 3] x = list1.count(2) print("The number 2 occurs " + str(x) + " times in the list.") Output: The number 2 occurs 3 times in the list.# Create a list of integers
list1 = [1, 2, 2, 7, 2, 9, 1, 4, 3]
x = list1.count(2)
print("The number 2 occurs " + str(x) + " times in the list.")
Output:
The number 2 occurs 3 times in the list.
Example 2:
Similarly, if you apply the same method to determine the same elements in strings.
# Create a list of Strings
list1 = ['mango', 'mango', 'guava', 'apple', 'guava', 'mango', 'apple']
x = list1.count('apple')
print("The Fruit 'apple' occurs " + str(x) + " times in the list.")
x = list1.count('orange')
print("The Fruit 'orange' occurs " + str(x) + " times in the list.")
“count the number of times an element appears in a list python in constant time” Code Answer’s
how to find no of times a elements in list python
python by Bst Barracuda on May 17 2020 Comment
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how to find the number of times a number appears in python
python by Itchy Ibis on Feb 24 2020 Comment
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Source: stackoverflow.com
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