Python program to remove Nth occurrence of the given word
Given a list of words in Python, the task is to remove the Nth occurrence of the given word in that list.
Examples:
Approach #1: By taking another list.
Make a new list, say newList. Iterate the elements in the list and check if the word to be removed matches the element and the occurrence number, otherwise, append the element to newList.
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# Python3 program to remove Nth
# occurrence of the given word
# Function to remove Ith word
def RemoveIthWord(lst, word, N):
newList = []
count = 0
# iterate the elements
for i in lst:
if(i == word):
count = count + 1
if(count != N):
newList.append(i)
else:
newList.append(i)
lst = newList
if count == 0:
print("Item not found")
else:
print("Updated list is: ", lst)
return newList
# Driver code
list = ["geeks", "for", "geeks"]
word = "geeks"
N = 2
RemoveIthWord(list, word, N)
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Output :
Updated list is: ['geeks', 'for']
Approach #2: Remove from the list itself.
Instead of making a new list, delete the matching element from the list itself. Iterate the elements in the list and check if the word to be removed matches the element and the occurrence number, If yes delete that item and return true. If True is returned, print List otherwise, print “Item not Found”.
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# Python3 program to remove Nth
# occurrence of the given word
# Function to remove Ith word
def RemoveIthWord(list, word, N):
count = 0
for i in range(0, len(list)):
if (list[i] == word):
count = count + 1
if(count == N):
del(list[i])
return True
return False
# Driver code
list = ['geeks', 'for', 'geeks']
word = 'geeks'
N = 2
flag = RemoveIthWord(list, word, N)
if (flag == True):
print("Updated list is: ", list)
else:
print("Item not Updated")
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Output :
Approach #3: Remove from the list using pop().
Instead of creating a new list and using if/else statement we can pop the matching element from the list using pop( ). We need to use an additional counter to keep track of the index.
Why we need an index ? because pop( ) needs index to pass inside i.e pop(index).
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# Python3 program to remove Nth
# occurrence of the given word
# Function to remove nth word
def omit(list1,word,n1):
# for counting the occurrence of word
count=0
# for counting the index number
# where we are at present
index=0
for i in list1:
index+=1
if i==word:
count+=1
if count==n1:
# (index-1) because in list
# indexing start from 0th position
list1.pop(index-1)
return list1
# Driver code
list1 = ["he", "is", "ankit", "is",
"raj", "is","ankit raj"]
word="is"
n1=3
print("new list is :",omit(list1,word,n1))
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Output :
new list is : ['he', 'is', 'ankit', 'is', 'raj', 'ankit raj']Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.
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Introduction
In this section of python programming, we will understand the code to eliminate the nth occurrence of the given element from the list.