a. 2FeCl3(aq) + H2S(g) " 2FeCl2 (aq) + 2HCl(aq) + S(s)
+3 -2 +2 0
Atom Fe dan S perlu diperiksa biloksnya karena mengalami perubahan tipe rumus. Biloks Fe berubah dari +3 menjadi +2 artinya Fe mengalami reduksi. Biloks S berubah dari -2 menjadi 0, artinya S mengalami oksidasi. Jadi, reaksi ini tergolong reaksi redoks.
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Berapa bilangan oksidasi Cr (kromium) dalam ion Cr2O72-?
Jawab:
Cara menentukan bilangan oksidasi Cr (kromium) dalam ion Cr2O72- adalah sebagai berikut:
Biloks O = -2 (aturan biloks)
Biloks Cr2O72- = -2 (ion)
Jadi biloks Cr dalam ion Cr2O72- adalah +6
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